From 67d4f6d1f2f996bfccb3c7ff4134d7180a78e5bf Mon Sep 17 00:00:00 2001
From: "Eric S. Raymond" <esr@thyrsus.com>
Date: Sun, 24 Aug 2003 17:34:16 +0000
Subject: [PATCH 1/1] Initial revision

---
 shredcompare.py | 98 +++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 98 insertions(+)
 create mode 100755 shredcompare.py

diff --git a/shredcompare.py b/shredcompare.py
new file mode 100755
index 0000000..85766ec
--- /dev/null
+++ b/shredcompare.py
@@ -0,0 +1,98 @@
+#!/usr/bin/env python
+#
+# shredcompare -- find similarities in file trees.
+#
+# Implements the shred algorithm described at:
+#
+#	http://theinquirer.net/?article=10061
+#
+#   "Here is the procedure for finding the matching code.... "1. Each
+#   file withing each source tree is "shredded" into 5 line pieces (1-5,
+#   2-6, 3-7, etc.). MD5 sum is computed for each block of lines. The
+#   output is 3 columns: MD5sum, source file, 1st line in the block.
+#   
+#   "At this stage, 4.4BSD had [a] ~40Mb file, linux ~160Mb. Potentially,
+#   one could shred into smaller or larger pieces, however, with pieces
+#   too small there'll be a lot of noise, with pieces too large some
+#   matches won't be seen. 5 liners seem to be a good compromise.
+#   
+#   "2. Within each source tree the "shredded" file is sorted by MD5sum,
+#   and duplicate entries within the same tree are removed completely
+#   (these are either trivial 5-line sequences or licensing
+#   disclaimers). Unix sort here takes a couple of minutes on a 600Mhz
+#   P3.
+#   
+#   "3. A column indicating the origin of the file is inserted into the
+#   file (0 - BSD, 1 - linux). Both Linux and BSD "shredded" files are
+#   merged such that MD5sums stay sorted.
+#   
+#   "4. At this point a given MD5sum will occur either once or twice,
+#   i.e., in both source trees. Here remove all thesingle lines, and have
+#   the 5 liners left that are matching.
+#   
+#   "5. Count for each file in Linux tree the number of matches with the
+#   BSD tree using the file generated at step 4. Sort this list, and the
+#   largest counts will occur for the files with the largest number of
+#   matching lines. The range can be extracted from the file from step 4,
+#   since at step 1 we kept the address of the 1st line in the
+#   block. That is how the info above was generated.
+#
+# In this implementation, lines are preprocessed to remove whitespace
+# differences.
+import sys, os, os.path, re, md5
+
+shredsize = 5
+ws = re.compile(r"\s+")
+
+def smash_whitespace(line):
+    "Replace each string of whitespace in a line with a single space."
+    return ws.sub(' ', line)
+
+def shredfile(file, tree):
+    "Build a dictionary of shred tuples corresponding to a specified file."
+    shreds = {}
+    fp = open(file)
+    lines = map(smash_whitespace, fp.readlines())
+    fp.close()
+    for i in range(len(lines)-shredsize):
+        m = md5.new()
+        for j in range(shredsize):
+            m.update(lines[i+j])
+        # Merging shreds into a dict automatically suppresses duplicates
+        shreds[m.digest()] = [file, i, i+shredsize]
+    return shreds
+
+def eligible(file):
+    "Is a file eligible for comparison?"
+    return filter(lambda x: file.endswith(x), ('.c', 'h', '.y', '.l', '.txt'))
+
+def shredtree(tree):
+    "Shred an entire file tree; return a dictionary of checksums-to-locations."
+    shreds = {}
+    # First, prepare the shred list.
+    for root, dirs, files in os.walk(tree):
+        for file in files:
+            path = os.path.join(root, file)
+            if eligible(path):
+                shreds.update(shredfile(path, tree))
+    return shreds
+
+def shredcompare(tree1, tree2):
+    "Compare two trees."
+    shreds1 = shredtree(tree1)
+    shreds2 = shredtree(tree2)
+    # Nuke everything but checksum matches between the trees
+    for key in shreds1.keys():
+        if not key in shreds2:
+            del shreds1[key]
+    for key in shreds2.keys():
+        if not key in shreds1:
+            del shreds2[key]
+    # Merge the match lists
+    matches = []
+    for key in shreds1.keys():
+        matches.append((shreds1[key], shreds2[key]))
+    return matches
+
+if __name__ == '__main__':
+    print shredcompare(sys.argv[1], sys.argv[2])
-- 
2.43.0